How do I simplify this expression?

by R. Burton   Last Updated November 18, 2018 18:20 PM

How do I simplify: $$d=\frac{-(x+\alpha x)^2+(y+\alpha y)^2+2+x^2-y^2-2}{\sqrt{\alpha x^2+\alpha y^2}}$$ If simplification is possible, it should be possible with elementary algebra, but I'm completely lost as to how to go about it.


What I've done so far: $$d=\frac{-(x+\alpha x)^2+(y+\alpha y)^2+2+x^2-y^2-2}{\sqrt{\alpha x^2+\alpha y^2}}$$ $$=\frac{-(x+\alpha x)^2+(y+\alpha y)^2+x^2-y^2}{\sqrt{\alpha x^2+\alpha y^2}}=\frac{-\alpha^2x^2+\alpha^2y^2-2\alpha x+2\alpha y}{\sqrt{\alpha x^2+\alpha y^2}}$$ $$\implies d^2=\left(\frac{(-a^2x^2+a^2y^2-2ax+2ay)^2}{a^2x^2+a^2y^2}\right)^2$$



Answers 1


I believe your third equality is incorrect. Numerator distribution won't lead to any terms with x and y to the first power.

Then when you squared d below, you also have additional squares added to a in denominator where there were none as well as a double square for the entire numerator and denominator - essentially you have d to the 4th power with a being squared on bottom where it wasn't in the initial equation.

user597562
user597562
November 18, 2018 18:19 PM

Related Questions


Polynomials with roots of unity as roots

Updated January 09, 2018 01:20 AM

Nature of roots of a biquadratic equation

Updated July 09, 2015 13:08 PM


Solving for the value of t

Updated September 13, 2017 18:20 PM

Closed algebraic form of $\cos(\frac{\pi}{7})$

Updated February 10, 2018 18:20 PM