solution to system of equations

by ashwani yadav   Last Updated August 10, 2018 05:20 AM

In a system of equations AX = B. by Cramer's rule if det(A)=0, then the system will have no solution but on the other hand, in non-homogeneous system of equations suppose the rank of square matrix nxn is (n-1) and rank of the augmented matrix[A|B] is also having the same rank but then we say that system is consistent, having rank < no. of variables implies infinitely many solutions.

how is this correct? I mean if the rank of A is n-1 < n and rank(A) = rank(A|B), then it also implies that determinant of square matrix nxn is zero but then we say it is consistent.

pls correct me if my theory is wrong too.

Answers 1

Cramer rule doesn't says that when determinant is zero, it has no solution. When the determinant is zero, the system can either have no solution (inconsistent) or infinitely many solutions (consistent).

Cramer rule gives us a way to compute the solution when the solution is unique.

Siong Thye Goh
Siong Thye Goh
August 10, 2018 05:13 AM

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