Why does the pivotal quantity $g(X,θ)$ have to be a monotonic function of $θ$ for a fixed $X$?

by HumptyDumpty   Last Updated August 13, 2019 21:19 PM

I'm learning about pivotal quantities, which are functions $g(X,θ)$ of the data $X$ and the parameter $θ$. One property they must satisfy is that $g(X,θ)$ is a monotonic function of $θ$ for a fixed $X$.

I'm told the reason for this, is to be able to manipulate inequalities.

For example, if we have a random sample

$X_1, X_2, ... , X_n$ from $N(θ,σ^2)$, we can construct a confidence interval for $θ$ by creating a pivotal quantity: $\frac{\bar X - \theta}{\sigma/\sqrt n}$

So that for example, $P(-1.96 \leq \frac{\bar X - \theta}{\sigma/\sqrt n} \leq 1.96) = 0.95$

Now, it is apparently this property of $\frac{\bar X - \theta}{\sigma/\sqrt n}$ being monotonic in $θ$ for a fixed $X$ that allows us to manipulate these inequalities and write this as

$P(\bar X - 1.96 \frac{σ}{\sqrt n} \leq θ \leq \bar X + 1.96 \frac{σ}{\sqrt n}) = 0.95$.

But I do not understand any part of this. Why does it need to be monotonic in $θ$? What does it mean for it to be monotonic in $θ$? Why does $X$ need to be fixed? Why does this let us manipulate the inequalities?

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